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用递等式计算.(1)406+4480÷28(2)1757-189-157(3)38÷(78-

2022-08-14 03:04:01 问答库 阅读 200 次

问题详情

用递等式计算.
(1)406+4480÷28
(2)175

7

-18

9

-15

7


(3)3

8

÷(7

8

-1

4

)×5.5
(4)1

3

÷5

4

+2

3

×4

5


(5)5-(1

12

+1

15

)×30
(6)[11

3

-(2.5-12

3

)]÷1

8

参考答案


(1)406+4480÷28,
=406+160,
=566;

(2)1757-189-157,
=1757-157-189,
=16-189,
=1419;

(3)38÷(78-14)×5.5,
=38÷58×5.5,
=35×5.5,
=3.3;

(4)13÷54+23×45,
=13×45+23×45,
=(13+23)×45,
=1×45,
=45;

(5)5-(112+115)×30,
=5-(112×30+115×30),
=5-(2.5+2),
=5-4.5,
=0.5;

(6)[113-(2.5-123)]÷18,
=[113-2.5+123]÷18,
=[113+123-2.5]÷18,
=[3-2.5]÷18,
=0.5÷18,
=4.

考点:等式