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递等式计算:(能简便的要简便)3110×7(12+1÷27)÷1579×38×5271118

2022-08-14 02:54:19 问答库 阅读 200 次

问题详情

递等式计算:(能简便的要简便)
31

10

×7(1

2

+1÷2

7

)÷15

7

9×3

8

×5

27

11

18

×5

9

+5

9

×7

18

2.35+2

9

÷1

9

+2.35 (1

4

+1

2

)÷(2

3

-2

5

)

(3

8

+1

4

)÷3

16

(3

4

+1

6

-3

24

)÷1

24

25÷(1

4

-1

9

)

参考答案

(1)3110×7,
=(3×7)+(110×7),
=21+710,
=21710;
(2)(12+1÷27)÷157,
=(12+1×72)×715,
=(12+72)×715,
=4×715,
=2815,
=11315;
(3)9×38×527,
=9×38×527,
=58;
(4)1118×59+59×718,
=(1118+718)×59,
=1×59,
=59;
(5)2.35+29÷19+2.35,
=2.35+29×91+2.35,
=2.35+2+2.35,
=6.7;
(6)(14+12)÷(23-25),
=34÷415,
=34×154,
=4516,
=21316;
(7)(38+14)÷316,
=(38+14)×163,
=38×163+14×163,
=2+43,
=313;
(8)(34+16-324)÷124,
=34×24+16×24-324×24,
=18+4-3,
=19;
(9)25÷(14-19),
=25÷(936-436),
=25×365,
=180.

考点:等式