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计算下面各题.(1)递等式计算:37÷(116+23)×103(2)解方程:45×(x+50

2022-08-14 02:43:29 问答库 阅读 200 次

问题详情

计算下面各题.
(1)递等式计算:3

7

÷(11

6

+2

3

)×10

3


(2)解方程:4

5

×(x+50%)=16
(3)简便计算:
7

8

×(1-75%)+1

4

+0.25×1

8


49.5×13.5+50.5×13-0.5×49.5.

参考答案


(1)37÷(116+23)×103,
=37÷52×103,
=635×103,
=47;

(2)45×(x+50%)=16,
45×(x+50%)÷45=16÷45,
x+50%=20,
x+50%-50%=20-50%,
x=19.5;

(3)78×(1-75%)+14+0.25×18,
=78×0.25+0.25+0.25×18,
=(78+1+18)×0.25,
=2×0.25,
=0.5;

49.5×13.5+50.5×13-0.5×49.5,
=49.5×13.5-0.5×49.5+50.5×13,
=49.5×(13.5-0.5)+50.5×13,
=49.5×13+50.5×13,
=(49.5+50.5)×13,
=100×13,
=1300.

考点:等式,方程