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计算 写出必要过程.92:x=247:0.5259+3910-5.22259-62750+5

2022-08-14 05:19:39 问答库 阅读 201 次

问题详情

计算,写出必要过程.
9

2

:x=24

7

:0.5
25

9

+39

10

-5.22

25

9

-627

50

+5.22

÷(2006×0.4

2008×0.5

+1.6

2008

)
2008×981

4

-225×101

25

+2004

5

×283

4


1+2-3+4+5-6+7+8-9+…+601+602-603+604+605-606.

参考答案

①92:x=247:0.5,
247x=92×0.5,
247x=94,
x=78;

②259+3910-5.22259-62750+5.22÷(2006×0.42008×0.5+1.62008),
=259-1.32259-1.32÷1606.42008,
=2008016064,
=12551004;
③2008×9814-225×10125+20045×2834,
=2008×3934-225×25125+10045×1154,
=197286-2259+5773,
=200800;
④1+2-3+4+5-6+7+8-9+..+601+602-603+604+605-606,
=(1+2-3)+(4+5-6)+(7+8-9)+…(604+605-606),
=0+3+6+9+…+603,
=(0+603)×202÷2,
=60903.

考点:过程