A-A+
用递等式计算.①[1-(18+23)]×36②(29+712)×36③7.5×4.7+4.7
问题详情
用递等式计算.
①[1-(
②(
③7.5×4.7+4.7×2.5
④25.3×12-33.46÷0.35
⑤
⑥
参考答案
①[1-(18+23)]×36,
=[1-(324+1624)]×36,
=[1-1924]×36,
=524×36,
=152;
②(29+712)×36,
=36×29+712×36,
=8+21,
=29;
③7.5×4.7+4.7×2.5,
=4.7×(7.5+2.5),
=4.7×10,
=47;
④25.3×12-33.46÷0.35,
=303.6-95.6,
=208;
⑤56×[23÷(1-1315)],
=56×[23÷215],
=56×[23×152],
=56×5,
=416;
⑥14+(58-310)÷12,
=14+(2540-1240)×2,
=14+1340×2,
=520+1320,
=910.
考点:等式