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用递等式计算.(可用简便算法)5710×310+310×31023+(47+12)×7258

2022-08-14 02:36:23 问答库 阅读 200 次

问题详情

用递等式计算.(可用简便算法)
57

10

×3

10

+3

10

×3

10


2

3

+(4

7

+1

2

)×7

25


8

13

÷7+1

7

×6

13


8

13

÷7+1

7

×7

13


(1

12

+1

2

-7

12

)÷1

7


11

5

÷0.24-1.6×3

4

参考答案

(1)5710×310+310×310,
=(5710+310)×310,
=6×310,
=95;

(2)23+(47+12)×725,
=23+1514×725,
=23+310,
=2930;

(3)813÷7+17×613,
=813×17+17×613,
=(813+613)×17,
=1413×17,
=213;

(4)813÷7+17×713,
=813×17+17×713,
=(813+713)×17,
=1513×17,
=1591;

(5)(112+12-712)÷17,
=(712-712)÷17,
=0÷17,
=0;

(6)115÷0.24-1.6×34,
=5-1.2,
=3.8.

考点:等式,算法