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用递等式计算.(1)370×203-19266÷38(2)32×3.1+1÷1.25(3)2

2022-08-14 02:46:39 问答库 阅读 200 次

问题详情

用递等式计算.
(1)370×203-19266÷38
(2)32×3.1+1÷1.25
(3)21

26

×(39÷35)÷0.9
(4)(9-3.06÷3

5

)×13

13


(5)(3-11

8

+11

7

)×18

13

-31

56

×56
(6)[(37

40

+0.075)÷3

25

-217

24

]×2

15

参考答案

(1)370×203-19266÷38,
=75110-507,
=74603;

(2)32×3.1+1÷1.25,
=9.92+0.8,
=10.72;

(3)2126×(39÷35)÷0.9,
=2126×3935÷0.9,
=0.9÷0.9,
=1;

(4)(9-3.06÷35)×1313,
=(9-5.1)×1313,
=3.9×1313,
=4.8;

(5)(3-118+117)×1813-3156×56,
=3×56-118×56+117×56,
=168-49+64,
=119+64,
=183;

(6)[(3740+0.075)÷325-21724]×215,
=[1÷325-21724]×215,
=[253-21724]×215,
=13524×215,
=34.

考点:等式