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递等式计算. (1)713×34+34×613(2)37÷711+47÷711(3)127÷

2022-08-14 02:40:59 问答库 阅读 200 次

问题详情

递等式计算. (1)7

13

×3

4

+3

4

×6

13

(2)3

7

÷7

11

+4

7

÷7

11

(3)12

7

÷(2

3

-1

4

)

(4)5

9

+5

9

÷5

3

(5)16

5

×1

2

÷2

5

(6)36×(7

9

+5

6

)÷29

5

(7)1

8

×56×2

7

(8)7×30%(9)1

6

×6%

(10)12×(1

2

+3

4

)(11)4÷4%

参考答案

(1)713×34+34×613,
=34×(713+613),
=34×1,
=34;

(2)37÷711+47÷711,
=(37+47)×711,
=1×711,
=711;

(3)127÷(23-14),
=127÷512,
=4435;

(4)59+59÷53,
=59+39,
=89;

(5)165×12÷25,
=85÷25,
=4;

(6)36×(79+56)÷295,
=(36×79+36×56)÷295,
=(28+30)÷295,
=58÷295,
=10;

(7)18×56×27,
=(18×8)×(7×27),
=1×2,
=2;

(8)7×30%=2.1;

(9)16×6%=0.01;

(10)12×(12+34),
=12×12+12×34,
=6+9,
=15;

(11)4÷4%=100.

考点:等式