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用递等式计算(能简单的要简单)①59+49×920÷65②1113+712-(1113-51

2022-08-14 02:38:18 问答库 阅读 200 次

问题详情

用递等式计算(能简单的要简单)
①5

9

+4

9

×9

20

÷6

5

②11

13

+7

12

-(11

13

-5

12

)③(1-25%)×101-3

4

④197×1

98

+1

98

⑤2

3

÷[3

4

×(17

18

-8

9

)]⑥1

2007

×2001+5

2007

+1

2007

⑦31

2

:x=13

4

:(1.6×5)

参考答案

①59+49×920÷65,
=59+15×56,
=59+16,
=1018+318,
=1318;

②1113+712-(1113-512),
=1113-1113+712+512,
=1;

③(1-25%)×101-34,
=75%×101-75%,
=(101-1)×75%,
=100×75%,
=75;

④197×198+198,
=(196+1)×198+198,
=196×198+1×198+198,
=2+198×2,
=2149;

⑤23÷[34×(1718-89)],
=23÷[34×(1718-1618)],
=23÷[34×118],
=23×24,
=16;

⑥12007×2001+52007+12007,
=20012007+52007+12007,
=1;

⑦312:x=134:(1.6×5),
134x=(1.6×5)×312,
134x÷134=8×312÷134,
x=16.

考点:等式