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用递等式计算(能简便计算的要写出简算过程).①[3.2×(1-58)+335]×2112②1

2022-08-14 02:12:20 问答库 阅读 200 次

问题详情

用递等式计算(能简便计算的要写出简算过程).
①[3.2×(1-5

8

)+33

5

]×21

12

②13

7

+24

15

+44

7

+32

15

43

97

×99

④3.75×42

5

+1.6×33

4

⑤1÷2.5+2.5×0.4⑥32

5

-13

4

-1

4

参考答案

①[3.2×(1-58)+335]×2112
=[315×(1-58)+335]×2112
=[315×38+335]×2112
=(65+185)×2512
=245×2512
=10;

②137+2415+447+3215
=(137+447)+(2415+3215),
=6+523
=1123

4397×99,
=4397×(97+2),
=4397×97+4397×2,
=43+8697
=438697

④3.75×425+1.6×334
=3.75×4.4+1.6×3.75,
=3.75×(4.4+1.6),
=3.75×6,
=22.5;

⑤1÷2.5+2.5×0.4,
=0.4+2.5×0.4,
=0.4×(1+2.5),
=0.4×3.5,
=1.4;

⑥325-134-14
=325-(134+14),
=325-2,
=125

考点:等式,过程