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用递等式计算 能简算的要简算 (417+125)×17×258.1÷〔(417-0.005×

2022-08-14 02:10:58 问答库 阅读 200 次

问题详情

用递等式计算,能简算的要简算 (4

17

+1

25

)×17×258.1÷〔(41

7

-0.005×700)÷12

7

+3〕

1234÷12341234

1235

9999×2222+3334×3333.

参考答案

(1)(417+125)×17×25,
=(417+125)×(17×25),
=(417×17×25)+(125×25×17),
=(4×25)+(1×17),
=100+17,
=117;

(2)8.1÷[(417-0.005×700)÷127+3],
=8.1÷[(417-3.5)÷127+3],
=8.1÷[914÷127+3],
=8.1÷[12+3],
=8.1÷312
=8135

(3)1234÷123412341235
=1234÷1234×1235+12341235
=1234÷1234×(1235+1)1235
=1234÷1234×12361235
=1234×12351234×1236
=12351236

(4)9999×2222+3334×3333,
=3333×6666+3334×3333,
=3333×(6666+3334),
=3333×10000,
=33330000.

考点:等式