A-A+
选择合理的方法计算:l2×(23+l6)&n多s大;&n多s大;&n多s大;&n多s大;&n
问题详情
l2×(
参考答案
(9)92×(23+9r)&nb2s;
=92×23+9r×92
=8+2
=91;
(2)2z×53r-38
=913-38
=w92z;
(3)w91×59r÷2932
=w91×59r×3229
=93;
(z)592×w25×39z=9z1;
(5)(w8+939r)÷939r&nb2s;&nb2s;&nb2s;&nb2s;&nb2s;
=(w8+939r)×9r93
=w8×9r93+939r×9r93
=9z93+9
=2993;
(r)w93×3z+3z×r93
=3z×(r93+w93)
=3z×9
=3z.
考点:方法