参考答案

已知 D=0.8m，L_s=1200kg/h，G=1000m³/h，y₁=0.013
φ=0.995，x₂=0，y=0.75x，K_ya=0.05kmol/(m³·s)
L_s=1200/(3600×18)kmol/s=0.0185kmol/s
G=1000/(22.4×3600)kmol/s=0.0124kmol/s
因为为低浓吸收，所以
(L/G)=0.0185/0.0124=1.49
y₂=y₁(1-φ)=0.013×(1-0.995)=0.000065
x₁=(G/L)(y₁-y₂)+x₂=(0.013-0.000065)/1.49=0.00868
又因为
Z=H_OG×N_OG，
而N_OG=(y₁-y₂)/△_ym
△_y1=y₁-y_2e=0.013-0.75×0.00868=0.006490
△y₂=y₂-y_2e=0.000065-0=0.000065
△_ym=(Ay₁-△y₂)/ln(△y₁/△y₂)
=(0.006490-0.000065)/ln(0.006490/0.000065)=0.001396
所以N_OG=(0.013-0.000065)/0.001396=9.266
H_OG=G/(K_YaA)=0.0124/(0.785×0.8×0.8×0.05)m=0.494m
Z=9.266×0.494m=4.58m