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Chlorine gas can be prepared by adding dilute

2022-08-11 22:49:04 问答库阅读 192 次

问题详情

Chlorine gas can be prepared by adding dilute HCl(aq) dropwise onto potassium permanganate crystals，KMnO₄. The KMnO₄ is reduced to Mn²⁺(aq). What volume (in liters) of 1.50mol·L^-1 HCl(aq) is required to react with 12.0g KMnO₄？

参考答案

2KMnO₄+16HCl===2MnCl₂+5Cl₂↑+8H₂O+2KCl
n(HCl)=8n(KMnO₄)=8m(KMnO₄)/M(KMnO₄)
=8×12.0g/]58g·mol^-1
=0.608mol
So： V(HCl)=n(HCl)/c(HCl)
=0.608mol/1.50mol·L^-1
=0.405L